It is common in php that you write codes but whenever you tried to display on the web browser it displays nothing even a html. You want to know the behind where actually problem occurs. In which line or in which part of the code. The error_reporting function will help in this case really well.
Below is an example which is written to display directory contents inside c:\Documents and Settings folder but at the end on the browser it displayed nothing. You by enabling error reporting I might wish the say what actually happening there.
Code
<html>
<body>
<?php
error_reporting(E_ALL);
ini_set('display_errors', true);
ini_set('html_errors', true);
$fileHandler = opendir('C:\Documents and Settings');
while (false !== ($file = readdir($filehandler))) {
$files[] = $file;
}
sort($files);
print_r($files);
closedir($filehandler);
?>
</body>
</html>
Output
Notice: Undefined variable: filehandler in C:\apache2triad\htdocs\array_file.php on line 8
Warning: readdir(): supplied argument is not a valid Directory resource in C:\apache2triad\htdocs\array_file.php on line 8
Warning: sort() expects parameter 1 to be array, null given in C:\apache2triad\htdocs\array_file.php on line 11
Notice: Undefined variable: filehandler in C:\apache2triad\htdocs\array_file.php on line 13
Warning: closedir(): supplied argument is not a valid Directory resource in C:\apache2triad\htdocs\array_file.php on line 13
Based on the output you are aware that there is problem with variable naming. As variable is case-sensitive in php so you can write the code as,
<html>
<body>
<?php
error_reporting(E_ALL);
ini_set('display_errors', true);
ini_set('html_errors', true);
$fileHandler = opendir('C:\Documents and Settings');
while (false !== ($file = readdir($fileHandler))) {
$files[] = $file;
}
sort($files);
print_r($files);
closedir($fileHandler);
?>
</body>
</html>
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